4m^2-4=16m

Solution for 4m^2-4=16m equation:

4m^2-4=16m

We move all terms to the left:

4m^2-4-(16m)=0

a = 4; b = -16; c = -4;
Δ = b2-4ac
Δ = -162-4·4·(-4)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{5}}{2*4}=\frac{16-8\sqrt{5}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{5}}{2*4}=\frac{16+8\sqrt{5}}{8}
$